Well, here's an exhaustively checking version. Not statically still of course.

    for x in range(1,101):
        print [
                          # %3 = 0
        [      x,         "Fizz"  ],
        [   "Buzz",     "FizzBuzz"] # %5 = 0
        ][x%3 == 0][x%5 == 0]

(I'll note this was hard to get than if-checks and pattern matching so I won't be replacing such logic with matrices in my Python program any time soon...)