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sonoffett
on Oct 11, 2014
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Spark Breaks Previous Large-Scale Sort Record
Perhaps I misunderstand your comment, but you actually don't need to sort to compute a median (see O(n) median of medians algorithm [1]).
[1]
http://en.wikipedia.org/wiki/Median_of_medians
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[1] http://en.wikipedia.org/wiki/Median_of_medians