Yes, but from the text it seemed like fsin was broken to begin with:
It is surprising that fsin is so inaccurate. I could perhaps forgive it for being inaccurate for extremely large inputs (which it is) but it is hard to forgive it for being so inaccurate on pi which is, ultimately, a very ‘normal’ input to the sin() function.
It is surprising that fsin is so inaccurate. I could perhaps forgive it for being inaccurate for extremely large inputs (which it is) but it is hard to forgive it for being so inaccurate on pi which is, ultimately, a very ‘normal’ input to the sin() function.