There's an interesting reason for the parallel bond wires to the output pin, and it's not to keep it from fusing. The problem is if you put 1A through a thin bond wire, there will be some voltage drop across the wire. So if the chip produces 5V at the die, it might be 4.9V at the 7805's pin, which is no good. So they run a second bond wire from the output pin to the regulator circuit. This sense wire has hardly any current through it, so it gives an accurate value of the output voltage. Thus, the 7805 can regulate the voltage on the output pin, rather than the voltage at the die pad.

TL;DR: one bond wire to the output carries the current and the second bond wire on the output senses the voltage.