How do you trivially construct `n^2-1 = (n+1).(n-1)` ? I feel like I'm failing a... | Hacker News

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tinco on May 11, 2014 | parent | context | favorite | on: The $13 Billion Mystery Angels

How do you trivially construct `n^2-1 = (n+1).(n-1)` ? I feel like I'm failing at basic algebra here, but I don't see it.

pluies on May 11, 2014 [–]

(n+1).(n-1) = n^2 - n + n - 1 = n^2 - 1

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