Now that I'm reading that ... isn't *every* subset of a finite set itself finite... | Hacker News

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ygra on March 11, 2014 | parent | context | favorite | on: Direct3D to OpenGL abstraction layer

Now that I'm reading that ... isn't every subset of a finite set itself finite (and thus limited)?

Demiurge on March 11, 2014 [–]

I'm not a native English speaker, but I think in colloquial terms, "limited" means "smaller than you might want" or something like that.

TazeTSchnitzel on March 12, 2014 | [–]

A limited subset would not be a complete implementation, yes.

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