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sauerbraten
on Jan 2, 2014
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Ask HN: What's your speciality, and what's your "F...
When !E(y,z), then also !E(z,y) (because symmetry). Also, E(y,x).
Thus !E(x,z), because E(y,x) and E(x,z) would imply E(y,z), which is false.
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Thus !E(x,z), because E(y,x) and E(x,z) would imply E(y,z), which is false.