That's the classical LISP way of doing it:

    (eq (mul a
             a)
        (pow a
             2))

or

    (eq
        (mul
             a
             a
        )
        (pow
             a
             2
        )
    )

x*x == pow(x,2)

We have a winner!

Actually, I'd suggest a slight improvement: x*x = x^2

x · x = x²

(== (* x x) (pow x 2))

(= * x x ^ x 2)

no yaml programming please :(

From the YAML inventor himself: https://yamlscript.org/

The length people go to avoid Lisp, only to reinvent it, badly.