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That's not what idempotent means. Idempotent means forall x, f(x)=f(f(x)). Most pure functions are not idempotent. Heck, f(f(x)) doesn't even type-check for most f. The typical name given to always getting the same results is just "pure". It doesn't depend on any implicit state anywhere.



Right you are. I wish I had an excuse for my mistake, but I don't.




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