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Assuming perfect energy transfer (fairly reasonable for conductive heating of water) with no losses to ambient, a starting temperature of 20 C, 1 L of water (which I assume to weigh 1 kg) and a 1800W kettle (the max you’ll find in America): no.

t = specific heat capacity of water * mass of water * degC deltaT / power

4.186 J/gC 1000g * 80C / 1800 J/s ~= 186 seconds




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