Assuming perfect energy transfer (fairly reasonable for conductive heating of water) with no losses to ambient, a starting temperature of 20 C, 1 L of water (which I assume to weigh 1 kg) and a 1800W kettle (the max you’ll find in America): no.
t = specific heat capacity of water * mass of water * degC deltaT / power
t = specific heat capacity of water * mass of water * degC deltaT / power
4.186 J/gC 1000g * 80C / 1800 J/s ~= 186 seconds