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"The reentry will occur between -51.6 degrees South and 51.6 degrees North" -> "We have no f** idea of where or when it will come down, but at least we can assess it won't hit Santa Claus".



Yes, and: “which is now predicted for around 18:56 CET on 8 March +/- 0.4 day”

Prediction specified down to the minute with but the error bars are measured in days.


Exactly. We can't calculate the re-entry of some batteries, but we managed to land on the moon half a century ago.


That's partly because the drag effect of the atmosphere depends on the solar activity. Meaning, depending solar activity an object will start aerobraking higher up or lower down in the atmosphere. That of course drastically impacts the time it takes the object to fall out of orbit and since we can't really predict solar activity we cannot precisely predict when nor where this battery pack will hit the ground.


The Moon landing was powered and had lots of telemetry. This is an uninstrumented, unpowered box that was released over three years ago.


Go to the nearest pond and skip rocks. Try to predict how many times a rock will skip.

This is a fundamental problem with chaotic probability.




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