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You still have to know that 0 is 0 and not O, and that 1 is 1 and not I or l.



but if mistake is made, and you wrote down L instead of 1, and sent me in a e-mail. I, knowing that it is crockford 32, would easily deduce what mistake was made.


Right, I didn't realize the decoder is specified to be lenient in that way, so the confounded characters are actually equivalent in the encoding.




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