I don't understand the need for the first example: Array.prototype.push.apply(a,... | Hacker News

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		Yansky on July 5, 2011 \| parent \| context \| favorite \| on: Advanced Javascript tips and tricks I don't understand the need for the first example: Array.prototype.push.apply(a, b); Isn't that what the concat() method is for?

tomstuart on July 5, 2011 [–]

Array.prototype.push.apply(a, b) modifies a in-place; a.concat(b) returns a copy of a with b appended to it.

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