``` \*(&i+1)='1'; ``` This line is UB, no? You are referencing some random, if a... | Hacker News

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sheepfleece on Dec 14, 2020 | parent | context | favorite | on: Pointers Are Complicated II, or: We need better la...

``` *(&i+1)='1'; ```

This line is UB, no? You are referencing some random, if adjacent, block of memory. Anything can happen.

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