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In this instance, you're only concerned with the average case.

Worst case is infinite: you just always take the path back in the direction of the entrance, and never even get past the first inlet.

Best case is O(n): you always take the path forward.




Yep, sorry, it quickly became apparent after rereading this that the original analysis was not worst-case. I have revised my comment to also include how I view calculating the actual time complexity since I didn't actually do that initially.




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