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int0x80
on Aug 16, 2018
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An introduction to libuv (2016)
What do you mean by accidentally copy?
struct embbed { ... uv_loop_t loop; ... } e1, e2; ... e1 = e2; ?
newnewpdro
on Aug 16, 2018
[–]
Presumably they're referring to copy via simple assignment vs. requiring a memcpy or pointer dereference. It's a b.s. argument.
int0x80
on Aug 16, 2018
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totally. Your comment was right.
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struct embbed { ... uv_loop_t loop; ... } e1, e2; ... e1 = e2; ?