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This does technically require that a union of those structs exists, even though it is not used. I don't know of any compiler for which this actually makes a difference though.



Ah, I misunderstood the context, you are right to clarify this.


I checked and we actually have a give union for everything. I didn't mention it because I accidentally got rid of it when simplifying my question (the original is full of macros).

Looks like we are in the clear! :)




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