>It is conjectured that pi is "normal" in the sense that the digits occur with equal liklihood.
That's only part of it. You need that every block occurs as often as every other block of equal length. So every digit occurs as often as every other digit; every pair of digits occurs as often as every other pair; every triple occurs as often as every other triple; and so on. So the number you give is not normal in base 3.
A consequence of normality is that every finite sequence of digits eventually appears.
That's only part of it. You need that every block occurs as often as every other block of equal length. So every digit occurs as often as every other digit; every pair of digits occurs as often as every other pair; every triple occurs as often as every other triple; and so on. So the number you give is not normal in base 3.
A consequence of normality is that every finite sequence of digits eventually appears.
http://en.wikipedia.org/wiki/Normal_number