varargs functions require at least one non-vararg parameter.
(As int_19h said:) On some architectures, vararg functions have their own distinct ABI, so (...) as a declaration is not compatible with any definition that doesn't also use (...).
varargs functions require at least one non-vararg parameter.
(As int_19h said:) On some architectures, vararg functions have their own distinct ABI, so (...) as a declaration is not compatible with any definition that doesn't also use (...).